tech priest praying 1+
Thus, in the end, we only need to solve for
π₯
2
β
π₯
β
1
=
0
x
2
βxβ1=0.
1
2
(
1
+
5
)
2
1
1.61803398875
π
Ο.
tech priest praying 1+
Thus, in the end, we only need to solve for
π₯
2
β
π₯
β
1
=
0
x
2
βxβ1... [more]